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Brass Calculation Formula for Pits, Trenches, Heaps and Plots

By Umer SattarUpdated 22 Oct 20263 min read

The basic brass calculation formula (length × width × height in feet, divided by 100) is printed on every site diary. Real sites are rarely perfect boxes, though: trenches have sloping sides, sand is dumped in cones, and plots dip at one corner. This guide gives the formula for each shape a supervisor actually meets, with numbers worked through so they can be checked on a phone calculator.

The brass calculation formula behind every shape

Brass = Volume in cubic feet ÷ 100
Brass = Volume in cubic metres ÷ 2.832

Everything below is just a way of finding the volume. Measure in feet wherever possible and convert inches before multiplying: 6 inches is 0.5 ft, 9 inches 0.75 ft, 3 inches 0.25 ft.

1. Rectangular pits and footings

Brass = L × W × D ÷ 100 × number of pits

Twelve footing pits of 4 ft × 4 ft × 5 ft: 4 × 4 × 5 = 80 CFT each, × 12 = 960 CFT = 9.6 brass of excavation.

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2. Trenches with sloping sides

Trenches in loose soil are dug wider at the top for safety. The cross-section is a trapezium, so average the top and bottom widths:

Brass = Length × ((Top width + Bottom width) ÷ 2) × Depth ÷ 100

A 60 ft plinth trench, 3 ft wide at the bottom, 4 ft at the top and 4 ft deep: 60 × 3.5 × 4 = 840 CFT = 8.4 brass. Using the top width alone would have billed 9.6 brass, 14% too much.

How do I measure the length of trenches for a whole building?

Use the centre-line length: add up the centre lines of all walls. Measuring outside lengths counts every corner twice.

3. Heaps of sand, gitti and murum

Round (conical) heap

Volume = π × r² × h ÷ 3      (r = radius at the base, h = height)

A cone of sand 12 ft across (r = 6 ft) and 4 ft high: 3.1416 × 36 × 4 ÷ 3 ≈ 151 CFT = 1.5 brass. To find the radius, walk around the heap with a tape: circumference ÷ 6.283.

Long heap along a road (a ridge)

A long heap has a roughly triangular cross-section:

Volume = Length × Base width × Height ÷ 2

A ridge of murum 40 ft long, 8 ft wide at the base and 3 ft high: 40 × 8 × 3 ÷ 2 = 480 CFT = 4.8 brass. A heap with a flattened top holds more; treat it as a trapezium instead (average of top and base widths).

Heaps on soft ground sink a few inches into it, and the edges spread. Measuring a heap is always a rough check; the levelled truck body before tipping is the fair measurement.

4. Round pits, wells and sumps

Volume = π × r² × D

A soak pit 5 ft across and 8 ft deep: 3.1416 × 2.5² × 8 ≈ 157 CFT = 1.57 brass of earth removed.

5. Uneven plots: the average depth method

For levelling or filling a plot whose ground isn't flat, surveyors take depths at several points on a grid and average them:

  1. Stretch strings to divide the plot into equal squares (for example every 10 ft).
  2. At each grid point, measure how much fill (or cut) is needed to reach the final level.
  3. Average all the readings, then multiply by the plot area.

A 50 ft × 40 ft plot with readings of 1.0, 1.5, 2.0, 1.2, 0.8 and 1.5 ft average 8 ÷ 6 = 1.333 ft. Volume = 2,000 × 1.333 ≈ 2,667 CFT = 26.7 brass, plus about 10–15% for compaction.

Allowances that change the order

Common allowances
SituationWhyTypical allowance
Excavated earth for transportDug soil loosens (bulking)+20 to 30%
Filling that will be compactedMaterial settles when rolled and watered+10 to 15%
Damp sandBulking makes it occupy more spaceBuy by weight or check moisture

These are planning figures; soil type and moisture change them, so a site engineer's judgement on the day matters.

Frequently asked questions

What is the brass calculation formula?

Brass = length × width × height in feet ÷ 100, or cubic metres ÷ 2.832.

How do I calculate brass for a trench with sloping sides?

Multiply length × average of top and bottom widths × depth, then divide by 100.

How do I calculate brass of a sand heap?

For a round heap use π × r² × h ÷ 3; for a long ridge use length × base width × height ÷ 2. Divide the cubic feet by 100.

How do I calculate brass for filling an uneven plot?

Take fill depths at grid points, average them, multiply by the plot area and divide by 100. Add 10–15% for compaction.

How many cubic metres is 1 brass?

2.832 cubic metres.

Keep reading

Sources: standard mensuration formulas (prism, frustum, cone, cylinder); 1 brass = 100 ft³ = 2.832 m³.